120133256024149 has 2 divisors, whose sum is σ = 120133256024150. Its totient is φ = 120133256024148.

The previous prime is 120133256024137. The next prime is 120133256024237. The reversal of 120133256024149 is 941420652331021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119342668301649 + 790587722500 = 10924407^2 + 889150^2 .

It is a cyclic number.

It is not a de Polignac number, because 120133256024149 - 2⁷ = 120133256024021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120133256004149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066628012074 + 60066628012075.

It is an arithmetic number, because the mean of its divisors is an integer number (60066628012075).

Almost surely, 2^{120133256024149} is an apocalyptic number.

It is an amenable number.

120133256024149 is a deficient number, since it is larger than the sum of its proper divisors (1).

120133256024149 is an equidigital number, since it uses as much as digits as its factorization.

120133256024149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 120133256024149 in words is "one hundred twenty trillion, one hundred thirty-three billion, two hundred fifty-six million, twenty-four thousand, one hundred forty-nine".