12013340434 has 4 divisors (see below), whose sum is σ = 18020010654. Its totient is φ = 6006670216.

The previous prime is 12013340407. The next prime is 12013340461. The reversal of 12013340434 is 43404331021.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (12013340407) and next prime (12013340461).

It can be written as a sum of positive squares in only one way, i.e., 11995725625 + 17614809 = 109525^2 + 4197^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12013340399 and 12013340408.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3003335107 + ... + 3003335110.

Almost surely, 2^12013340434 is an apocalyptic number.

12013340434 is a deficient number, since it is larger than the sum of its proper divisors (6006670220).

12013340434 is an equidigital number, since it uses as much as digits as its factorization.

12013340434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6006670219.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 12013340434 its reverse (43404331021), we get a palindrome (55417671455).

The spelling of 12013340434 in words is "twelve billion, thirteen million, three hundred forty thousand, four hundred thirty-four".