12013401181 has 2 divisors, whose sum is σ = 12013401182. Its totient is φ = 12013401180.

The previous prime is 12013401173. The next prime is 12013401217. The reversal of 12013401181 is 18110431021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7967169081 + 4046232100 = 89259^2 + 63610^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013401181 - 2³ = 12013401173 is a prime.

It is a super-3 number, since 3×12013401181³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013401131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006700590 + 6006700591.

It is an arithmetic number, because the mean of its divisors is an integer number (6006700591).

Almost surely, 2^12013401181 is an apocalyptic number.

It is an amenable number.

12013401181 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013401181 is an equidigital number, since it uses as much as digits as its factorization.

12013401181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 22.

The spelling of 12013401181 in words is "twelve billion, thirteen million, four hundred one thousand, one hundred eighty-one".