1201341433141 has 4 divisors (see below), whose sum is σ = 1201346071884. Its totient is φ = 1201336794400.

The previous prime is 1201341433133. The next prime is 1201341433151. The reversal of 1201341433141 is 1413341431021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 618975562500 + 582365870641 = 786750^2 + 763129^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201341433141 - 2³ = 1201341433133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201341433151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1906390 + ... + 2457031.

It is an arithmetic number, because the mean of its divisors is an integer number (300336517971).

Almost surely, 2^{1201341433141} is an apocalyptic number.

It is an amenable number.

1201341433141 is a deficient number, since it is larger than the sum of its proper divisors (4638743).

1201341433141 is an equidigital number, since it uses as much as digits as its factorization.

1201341433141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4638742.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1201341433141 its reverse (1413341431021), we get a palindrome (2614682864162).

The spelling of 1201341433141 in words is "one trillion, two hundred one billion, three hundred forty-one million, four hundred thirty-three thousand, one hundred forty-one".