120134211322 has 4 divisors (see below), whose sum is σ = 180201316986. Its totient is φ = 60067105660.

The previous prime is 120134211299. The next prime is 120134211331. The reversal of 120134211322 is 223112431021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 223112431021 = 103 ⋅2166140107.

It can be written as a sum of positive squares in only one way, i.e., 92952424161 + 27181787161 = 304881^2 + 164869^2 .

It is a junction number, because it is equal to n+sod(n) for n = 120134211293 and 120134211302.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30033552829 + ... + 30033552832.

Almost surely, 2^120134211322 is an apocalyptic number.

120134211322 is a deficient number, since it is larger than the sum of its proper divisors (60067105664).

120134211322 is an equidigital number, since it uses as much as digits as its factorization.

120134211322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60067105663.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 120134211322 its reverse (223112431021), we get a palindrome (343246642343).

The spelling of 120134211322 in words is "one hundred twenty billion, one hundred thirty-four million, two hundred eleven thousand, three hundred twenty-two".