Base | Representation |
---|---|
bin | 1010111011010001011111… |
… | …0001011001110000101111 |
3 | 1120112110202001121022021111 |
4 | 2232310113301121300233 |
5 | 3033311442110302310 |
6 | 41314520125412451 |
7 | 2346640543102225 |
oct | 256642761316057 |
9 | 46473661538244 |
10 | 12013422353455 |
11 | 39119558026a6 |
12 | 1420346a0a127 |
13 | 691b2642b573 |
14 | 2d764a48ab15 |
15 | 15c76b49e28a |
hex | aed17c59c2f |
12013422353455 has 16 divisors (see below), whose sum is σ = 14420635454880. Its totient is φ = 9607719240832.
The previous prime is 12013422353417. The next prime is 12013422353459. The reversal of 12013422353455 is 55435322431021.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12013422353455 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12013422353459) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 324501936 + ... + 324538954.
It is an arithmetic number, because the mean of its divisors is an integer number (901289715930).
Almost surely, 212013422353455 is an apocalyptic number.
12013422353455 is a deficient number, since it is larger than the sum of its proper divisors (2407213101425).
12013422353455 is a wasteful number, since it uses less digits than its factorization.
12013422353455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55658.
The product of its (nonzero) digits is 432000, while the sum is 40.
Adding to 12013422353455 its reverse (55435322431021), we get a palindrome (67448744784476).
The spelling of 12013422353455 in words is "twelve trillion, thirteen billion, four hundred twenty-two million, three hundred fifty-three thousand, four hundred fifty-five".
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