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12013422353455 = 546371399737019
BaseRepresentation
bin1010111011010001011111…
…0001011001110000101111
31120112110202001121022021111
42232310113301121300233
53033311442110302310
641314520125412451
72346640543102225
oct256642761316057
946473661538244
1012013422353455
1139119558026a6
121420346a0a127
13691b2642b573
142d764a48ab15
1515c76b49e28a
hexaed17c59c2f

12013422353455 has 16 divisors (see below), whose sum is σ = 14420635454880. Its totient is φ = 9607719240832.

The previous prime is 12013422353417. The next prime is 12013422353459. The reversal of 12013422353455 is 55435322431021.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12013422353455 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013422353459) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 324501936 + ... + 324538954.

It is an arithmetic number, because the mean of its divisors is an integer number (901289715930).

Almost surely, 212013422353455 is an apocalyptic number.

12013422353455 is a deficient number, since it is larger than the sum of its proper divisors (2407213101425).

12013422353455 is a wasteful number, since it uses less digits than its factorization.

12013422353455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55658.

The product of its (nonzero) digits is 432000, while the sum is 40.

Adding to 12013422353455 its reverse (55435322431021), we get a palindrome (67448744784476).

The spelling of 12013422353455 in words is "twelve trillion, thirteen billion, four hundred twenty-two million, three hundred fifty-three thousand, four hundred fifty-five".

Divisors: 1 5 4637 13997 23185 37019 69985 185095 64904089 171657103 324520445 518154943 858285515 2590774715 2402684470691 12013422353455