Base | Representation |
---|---|
bin | 10110011000000111… |
… | …01001100000111011 |
3 | 1011000020102010212012 |
4 | 23030003221200323 |
5 | 144100420140011 |
6 | 5304025440135 |
7 | 603463403354 |
oct | 131403514073 |
9 | 34006363765 |
10 | 12013443131 |
11 | 51053036a8 |
12 | 23b334004b |
13 | 1195b90641 |
14 | 81d71ad2b |
15 | 4a4a28a8b |
hex | 2cc0e983b |
12013443131 has 8 divisors (see below), whose sum is σ = 12273228864. Its totient is φ = 11753831680.
The previous prime is 12013443121. The next prime is 12013443173. The reversal of 12013443131 is 13134431021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12013443131 - 218 = 12013180987 is a prime.
It is a super-2 number, since 2×120134431312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12013443097 and 12013443106.
It is not an unprimeable number, because it can be changed into a prime (12013443121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100901 + ... + 184953.
It is an arithmetic number, because the mean of its divisors is an integer number (1534153608).
Almost surely, 212013443131 is an apocalyptic number.
12013443131 is a deficient number, since it is larger than the sum of its proper divisors (259785733).
12013443131 is an equidigital number, since it uses as much as digits as its factorization.
12013443131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87141.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 12013443131 its reverse (13134431021), we get a palindrome (25147874152).
The spelling of 12013443131 in words is "twelve billion, thirteen million, four hundred forty-three thousand, one hundred thirty-one".
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