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12013443131 = 47304184053
BaseRepresentation
bin10110011000000111…
…01001100000111011
31011000020102010212012
423030003221200323
5144100420140011
65304025440135
7603463403354
oct131403514073
934006363765
1012013443131
1151053036a8
1223b334004b
131195b90641
1481d71ad2b
154a4a28a8b
hex2cc0e983b

12013443131 has 8 divisors (see below), whose sum is σ = 12273228864. Its totient is φ = 11753831680.

The previous prime is 12013443121. The next prime is 12013443173. The reversal of 12013443131 is 13134431021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12013443131 - 218 = 12013180987 is a prime.

It is a super-2 number, since 2×120134431312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12013443097 and 12013443106.

It is not an unprimeable number, because it can be changed into a prime (12013443121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100901 + ... + 184953.

It is an arithmetic number, because the mean of its divisors is an integer number (1534153608).

Almost surely, 212013443131 is an apocalyptic number.

12013443131 is a deficient number, since it is larger than the sum of its proper divisors (259785733).

12013443131 is an equidigital number, since it uses as much as digits as its factorization.

12013443131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87141.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 12013443131 its reverse (13134431021), we get a palindrome (25147874152).

The spelling of 12013443131 in words is "twelve billion, thirteen million, four hundred forty-three thousand, one hundred thirty-one".

Divisors: 1 47 3041 84053 142927 3950491 255605173 12013443131