Base | Representation |
---|---|
bin | 110111111100010010… |
… | …0100100001110110011 |
3 | 102111002101011111011121 |
4 | 1233320210210032303 |
5 | 3432013404432042 |
6 | 131104454123111 |
7 | 11452020665113 |
oct | 1577044441663 |
9 | 374071144147 |
10 | 120134452147 |
11 | 46a48847aa6 |
12 | 1b348950497 |
13 | b437001458 |
14 | 5b59145043 |
15 | 31d1bb3367 |
hex | 1bf89243b3 |
120134452147 has 2 divisors, whose sum is σ = 120134452148. Its totient is φ = 120134452146.
The previous prime is 120134452111. The next prime is 120134452183. The reversal of 120134452147 is 741254431021.
It is a balanced prime because it is at equal distance from previous prime (120134452111) and next prime (120134452183).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120134452147 is a prime.
It is not a weakly prime, because it can be changed into another prime (120134452847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60067226073 + 60067226074.
It is an arithmetic number, because the mean of its divisors is an integer number (60067226074).
Almost surely, 2120134452147 is an apocalyptic number.
120134452147 is a deficient number, since it is larger than the sum of its proper divisors (1).
120134452147 is an equidigital number, since it uses as much as digits as its factorization.
120134452147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 34.
Adding to 120134452147 its reverse (741254431021), we get a palindrome (861388883168).
The spelling of 120134452147 in words is "one hundred twenty billion, one hundred thirty-four million, four hundred fifty-two thousand, one hundred forty-seven".
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