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12013462240301 is a prime number
BaseRepresentation
bin1010111011010001101000…
…1001100011110000101101
31120112110211211122202202002
42232310122021203300231
53033312032313142201
641314524112342045
72346641536116344
oct256643211436055
946473754582662
1012013462240301
113911976276235
121420358244925
13691b31785752
142d76518b0b5b
1515c76ec2c76b
hexaed1a263c2d

12013462240301 has 2 divisors, whose sum is σ = 12013462240302. Its totient is φ = 12013462240300.

The previous prime is 12013462240249. The next prime is 12013462240319. The reversal of 12013462240301 is 10304226431021.

12013462240301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10858514391076 + 1154947849225 = 3295226^2 + 1074685^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013462240301 - 26 = 12013462240237 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013462240331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006731120150 + 6006731120151.

It is an arithmetic number, because the mean of its divisors is an integer number (6006731120151).

Almost surely, 212013462240301 is an apocalyptic number.

It is an amenable number.

12013462240301 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013462240301 is an equidigital number, since it uses as much as digits as its factorization.

12013462240301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 12013462240301 its reverse (10304226431021), we get a palindrome (22317688671322).

The spelling of 12013462240301 in words is "twelve trillion, thirteen billion, four hundred sixty-two million, two hundred forty thousand, three hundred one".