1201346224031 has 16 divisors (see below), whose sum is σ = 1315404023040. Its totient is φ = 1092240560640.

The previous prime is 1201346223901. The next prime is 1201346224061. The reversal of 1201346224031 is 1304226431021.

It is a cyclic number.

It is not a de Polignac number, because 1201346224031 - 2¹⁴ = 1201346207647 is a prime.

It is a super-2 number, since 2×1201346224031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1201346223985 and 1201346224003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201346224061) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1752776 + ... + 2339853.

It is an arithmetic number, because the mean of its divisors is an integer number (82212751440).

Almost surely, 2^{1201346224031} is an apocalyptic number.

1201346224031 is a deficient number, since it is larger than the sum of its proper divisors (114057799009).

1201346224031 is a wasteful number, since it uses less digits than its factorization.

1201346224031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4093234.

The product of its (nonzero) digits is 6912, while the sum is 29.

The spelling of 1201346224031 in words is "one trillion, two hundred one billion, three hundred forty-six million, two hundred twenty-four thousand, thirty-one".