12013567439 has 2 divisors, whose sum is σ = 12013567440. Its totient is φ = 12013567438.

The previous prime is 12013567411. The next prime is 12013567451. The reversal of 12013567439 is 93476531021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12013567439 - 2³² = 7718600143 is a prime.

It is a super-2 number, since 2×12013567439² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12013567396 and 12013567405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013567409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006783719 + 6006783720.

It is an arithmetic number, because the mean of its divisors is an integer number (6006783720).

Almost surely, 2^12013567439 is an apocalyptic number.

12013567439 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013567439 is an equidigital number, since it uses as much as digits as its factorization.

12013567439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 41.

The spelling of 12013567439 in words is "twelve billion, thirteen million, five hundred sixty-seven thousand, four hundred thirty-nine".