120140113 has 4 divisors (see below), whose sum is σ = 120351088. Its totient is φ = 119929140.

The previous prime is 120140099. The next prime is 120140117. The reversal of 120140113 is 311041021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311041021 = 157 ⋅1981153.

It is a cyclic number.

It is not a de Polignac number, because 120140113 - 2¹⁷ = 120009041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120140093 and 120140102.

It is not an unprimeable number, because it can be changed into a prime (120140117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 104631 + ... + 105772.

It is an arithmetic number, because the mean of its divisors is an integer number (30087772).

Almost surely, 2^120140113 is an apocalyptic number.

It is an amenable number.

120140113 is a deficient number, since it is larger than the sum of its proper divisors (210975).

120140113 is an equidigital number, since it uses as much as digits as its factorization.

120140113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 210974.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 120140113 is about 10960.8445386293. The cubic root of 120140113 is about 493.4343115167.

Adding to 120140113 its reverse (311041021), we get a palindrome (431181134).

It can be divided in two parts, 1201 and 40113, that added together give a palindrome (41314).

The spelling of 120140113 in words is "one hundred twenty million, one hundred forty thousand, one hundred thirteen".