12014013053501 has 4 divisors (see below), whose sum is σ = 12293408705952. Its totient is φ = 11734617401052.

The previous prime is 12014013053459. The next prime is 12014013053527. The reversal of 12014013053501 is 10535031041021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12014013053501 - 2²² = 12014008859197 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12014013053551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139697826161 + ... + 139697826246.

It is an arithmetic number, because the mean of its divisors is an integer number (3073352176488).

Almost surely, 2^{12014013053501} is an apocalyptic number.

It is an amenable number.

12014013053501 is a deficient number, since it is larger than the sum of its proper divisors (279395652451).

12014013053501 is an equidigital number, since it uses as much as digits as its factorization.

12014013053501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 279395652450.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 12014013053501 its reverse (10535031041021), we get a palindrome (22549044094522).

The spelling of 12014013053501 in words is "twelve trillion, fourteen billion, thirteen million, fifty-three thousand, five hundred one".