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1201403431973 is a prime number
BaseRepresentation
bin10001011110111001001…
…110011000110000100101
311020212000212111211201102
4101132321032120300211
5124140433234310343
62315530033005445
7152540616451313
oct21367116306045
94225025454642
101201403431973
1142356aa0a328
12174a0b6b3885
13893a4298624
1442210a910b3
15213b800c3b8
hex117b9398c25

1201403431973 has 2 divisors, whose sum is σ = 1201403431974. Its totient is φ = 1201403431972.

The previous prime is 1201403431951. The next prime is 1201403432059. The reversal of 1201403431973 is 3791343041021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 998274744769 + 203128687204 = 999137^2 + 450698^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201403431973 - 212 = 1201403427877 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201403431903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600701715986 + 600701715987.

It is an arithmetic number, because the mean of its divisors is an integer number (600701715987).

Almost surely, 21201403431973 is an apocalyptic number.

It is an amenable number.

1201403431973 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201403431973 is an equidigital number, since it uses as much as digits as its factorization.

1201403431973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 38.

Adding to 1201403431973 its reverse (3791343041021), we get a palindrome (4992746472994).

The spelling of 1201403431973 in words is "one trillion, two hundred one billion, four hundred three million, four hundred thirty-one thousand, nine hundred seventy-three".