12014106431555 has 4 divisors (see below), whose sum is σ = 14416927717872. Its totient is φ = 9611285145240.

The previous prime is 12014106431507. The next prime is 12014106431557. The reversal of 12014106431555 is 55513460141021.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12014106431555 - 2¹² = 12014106427459 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12014106431557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1201410643151 + ... + 1201410643160.

It is an arithmetic number, because the mean of its divisors is an integer number (3604231929468).

Almost surely, 2^{12014106431555} is an apocalyptic number.

12014106431555 is a deficient number, since it is larger than the sum of its proper divisors (2402821286317).

12014106431555 is an equidigital number, since it uses as much as digits as its factorization.

12014106431555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2402821286316.

The product of its (nonzero) digits is 72000, while the sum is 38.

Adding to 12014106431555 its reverse (55513460141021), we get a palindrome (67527566572576).

The spelling of 12014106431555 in words is "twelve trillion, fourteen billion, one hundred six million, four hundred thirty-one thousand, five hundred fifty-five".