120142244333 has 4 divisors (see below), whose sum is σ = 120288581628. Its totient is φ = 119995907040.

The previous prime is 120142244293. The next prime is 120142244423. The reversal of 120142244333 is 333442241021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 333442241021 = 431 ⋅773647891.

It can be written as a sum of positive squares in 2 ways, for example, as 39771128329 + 80371116004 = 199427^2 + 283498^2 .

It is a cyclic number.

It is not a de Polignac number, because 120142244333 - 2²² = 120138050029 is a prime.

It is a super-2 number, since 2×120142244333² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120142244296 and 120142244305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120142244533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73167416 + ... + 73169057.

It is an arithmetic number, because the mean of its divisors is an integer number (30072145407).

Almost surely, 2^120142244333 is an apocalyptic number.

It is an amenable number.

120142244333 is a deficient number, since it is larger than the sum of its proper divisors (146337295).

120142244333 is an equidigital number, since it uses as much as digits as its factorization.

120142244333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 146337294.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 120142244333 its reverse (333442241021), we get a palindrome (453584485354).

The spelling of 120142244333 in words is "one hundred twenty billion, one hundred forty-two million, two hundred forty-four thousand, three hundred thirty-three".