Base | Representation |
---|---|
bin | 1010111011010100110111… |
… | …0111110011011110110110 |
3 | 1120112120002022111121002121 |
4 | 2232311031313303132312 |
5 | 3033320321440020314 |
6 | 41315150151430154 |
7 | 2350002204013033 |
oct | 256651567633666 |
9 | 46476068447077 |
10 | 12014330001334 |
11 | 3912281088a11 |
12 | 142055a98535a |
13 | 691c3c4a200b |
14 | 2d76d4c3838a |
15 | 15c7c0edbd24 |
hex | aed4ddf37b6 |
12014330001334 has 4 divisors (see below), whose sum is σ = 18021495002004. Its totient is φ = 6007165000666.
The previous prime is 12014330001301. The next prime is 12014330001347. The reversal of 12014330001334 is 43310003341021.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 12014330001299 and 12014330001308.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3003582500332 + ... + 3003582500335.
It is an arithmetic number, because the mean of its divisors is an integer number (4505373750501).
Almost surely, 212014330001334 is an apocalyptic number.
12014330001334 is a deficient number, since it is larger than the sum of its proper divisors (6007165000670).
12014330001334 is an equidigital number, since it uses as much as digits as its factorization.
12014330001334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6007165000669.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 12014330001334 its reverse (43310003341021), we get a palindrome (55324333342355).
The spelling of 12014330001334 in words is "twelve trillion, fourteen billion, three hundred thirty million, one thousand, three hundred thirty-four".
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