Search a number
-
+
12014330001334 = 26007165000667
BaseRepresentation
bin1010111011010100110111…
…0111110011011110110110
31120112120002022111121002121
42232311031313303132312
53033320321440020314
641315150151430154
72350002204013033
oct256651567633666
946476068447077
1012014330001334
113912281088a11
12142055a98535a
13691c3c4a200b
142d76d4c3838a
1515c7c0edbd24
hexaed4ddf37b6

12014330001334 has 4 divisors (see below), whose sum is σ = 18021495002004. Its totient is φ = 6007165000666.

The previous prime is 12014330001301. The next prime is 12014330001347. The reversal of 12014330001334 is 43310003341021.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 12014330001299 and 12014330001308.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3003582500332 + ... + 3003582500335.

It is an arithmetic number, because the mean of its divisors is an integer number (4505373750501).

Almost surely, 212014330001334 is an apocalyptic number.

12014330001334 is a deficient number, since it is larger than the sum of its proper divisors (6007165000670).

12014330001334 is an equidigital number, since it uses as much as digits as its factorization.

12014330001334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6007165000669.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 12014330001334 its reverse (43310003341021), we get a palindrome (55324333342355).

The spelling of 12014330001334 in words is "twelve trillion, fourteen billion, three hundred thirty million, one thousand, three hundred thirty-four".

Divisors: 1 2 6007165000667 12014330001334