12014332000001 has 2 divisors, whose sum is σ = 12014332000002. Its totient is φ = 12014332000000.

The previous prime is 12014331999959. The next prime is 12014332000019. The reversal of 12014332000001 is 10000023341021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12006751685776 + 7580314225 = 3465076^2 + 87065^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12014332000001 is a prime.

It is not a weakly prime, because it can be changed into another prime (12014332000301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007166000000 + 6007166000001.

It is an arithmetic number, because the mean of its divisors is an integer number (6007166000001).

Almost surely, 2^{12014332000001} is an apocalyptic number.

It is an amenable number.

12014332000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

12014332000001 is an equidigital number, since it uses as much as digits as its factorization.

12014332000001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 12014332000001 its reverse (10000023341021), we get a palindrome (22014355341022).

The spelling of 12014332000001 in words is "twelve trillion, fourteen billion, three hundred thirty-two million, one", and thus it is an aban number.