1201434321341 has 4 divisors (see below), whose sum is σ = 1201464913632. Its totient is φ = 1201403729052.

The previous prime is 1201434321337. The next prime is 1201434321349. The reversal of 1201434321341 is 1431234341021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1201434321341 - 2² = 1201434321337 is a prime.

It is a super-2 number, since 2×1201434321341² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201434321349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15237161 + ... + 15315806.

It is an arithmetic number, because the mean of its divisors is an integer number (300366228408).

Almost surely, 2^{1201434321341} is an apocalyptic number.

It is an amenable number.

1201434321341 is a deficient number, since it is larger than the sum of its proper divisors (30592291).

1201434321341 is an equidigital number, since it uses as much as digits as its factorization.

1201434321341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30592290.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1201434321341 its reverse (1431234341021), we get a palindrome (2632668662362).

The spelling of 1201434321341 in words is "one trillion, two hundred one billion, four hundred thirty-four million, three hundred twenty-one thousand, three hundred forty-one".