1201443120041 has 2 divisors, whose sum is σ = 1201443120042. Its totient is φ = 1201443120040.

The previous prime is 1201443120029. The next prime is 1201443120071. The reversal of 1201443120041 is 1400213441021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1142889283600 + 58553836441 = 1069060^2 + 241979^2 .

It is an emirp because it is prime and its reverse (1400213441021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1201443120041 - 2³⁰ = 1200369378217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201443119989 and 1201443120016.

It is not a weakly prime, because it can be changed into another prime (1201443120001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600721560020 + 600721560021.

It is an arithmetic number, because the mean of its divisors is an integer number (600721560021).

Almost surely, 2^{1201443120041} is an apocalyptic number.

It is an amenable number.

1201443120041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201443120041 is an equidigital number, since it uses as much as digits as its factorization.

1201443120041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1201443120041 its reverse (1400213441021), we get a palindrome (2601656561062).

The spelling of 1201443120041 in words is "one trillion, two hundred one billion, four hundred forty-three million, one hundred twenty thousand, forty-one".