Base | Representation |
---|---|
bin | 10110011000001110… |
… | …11100111001110011 |
3 | 1011000022021210101011 |
4 | 23030013130321303 |
5 | 144101144040201 |
6 | 5304103051351 |
7 | 603505025005 |
oct | 131407347163 |
9 | 34008253334 |
10 | 12014440051 |
11 | 51059246a9 |
12 | 23b3740b57 |
13 | 119614c333 |
14 | 81d8da375 |
15 | 4a4b74151 |
hex | 2cc1dce73 |
12014440051 has 2 divisors, whose sum is σ = 12014440052. Its totient is φ = 12014440050.
The previous prime is 12014440033. The next prime is 12014440063. The reversal of 12014440051 is 15004441021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12014440051 - 25 = 12014440019 is a prime.
It is not a weakly prime, because it can be changed into another prime (12014440021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007220025 + 6007220026.
It is an arithmetic number, because the mean of its divisors is an integer number (6007220026).
Almost surely, 212014440051 is an apocalyptic number.
12014440051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014440051 is an equidigital number, since it uses as much as digits as its factorization.
12014440051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 640, while the sum is 22.
Adding to 12014440051 its reverse (15004441021), we get a palindrome (27018881072).
The spelling of 12014440051 in words is "twelve billion, fourteen million, four hundred forty thousand, fifty-one".
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