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12014557 = 79152083
BaseRepresentation
bin101101110101…
…001111011101
3211121101212121
4231311033131
511033431212
61105302541
7204056602
oct55651735
924541777
1012014557
116866795
124034a51
132648809
14184a6a9
1510c4d07
hexb753dd

12014557 has 4 divisors (see below), whose sum is σ = 12166720. Its totient is φ = 11862396.

The previous prime is 12014539. The next prime is 12014609. The reversal of 12014557 is 75541021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 75541021 = 157481153.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12014557 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12014537) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75963 + ... + 76120.

It is an arithmetic number, because the mean of its divisors is an integer number (3041680).

Almost surely, 212014557 is an apocalyptic number.

It is an amenable number.

12014557 is a deficient number, since it is larger than the sum of its proper divisors (152163).

12014557 is an equidigital number, since it uses as much as digits as its factorization.

12014557 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 152162.

The product of its (nonzero) digits is 1400, while the sum is 25.

The square root of 12014557 is about 3466.2021002821. The cubic root of 12014557 is about 229.0353866865.

Adding to 12014557 its reverse (75541021), we get a palindrome (87555578).

The spelling of 12014557 in words is "twelve million, fourteen thousand, five hundred fifty-seven".

Divisors: 1 79 152083 12014557