Base | Representation |
---|---|
bin | 10110011000010010… |
… | …01010011011101011 |
3 | 1011000100010120210011 |
4 | 23030021022123223 |
5 | 144101302414213 |
6 | 5304120432351 |
7 | 603511603660 |
oct | 131411123353 |
9 | 34010116704 |
10 | 12014888683 |
11 | 5106100776 |
12 | 23b39186b7 |
13 | 11962785b5 |
14 | 81d9b5a67 |
15 | 4a4c1203d |
hex | 2cc24a6eb |
12014888683 has 4 divisors (see below), whose sum is σ = 13731301360. Its totient is φ = 10298476008.
The previous prime is 12014888681. The next prime is 12014888687. The reversal of 12014888683 is 38688841021.
12014888683 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12014888683 - 21 = 12014888681 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12014888681) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 858206328 + ... + 858206341.
It is an arithmetic number, because the mean of its divisors is an integer number (3432825340).
Almost surely, 212014888683 is an apocalyptic number.
12014888683 is a deficient number, since it is larger than the sum of its proper divisors (1716412677).
12014888683 is an equidigital number, since it uses as much as digits as its factorization.
12014888683 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1716412676.
The product of its (nonzero) digits is 589824, while the sum is 49.
It can be divided in two parts, 1201 and 4888683, that added together give a palindrome (4889884).
The spelling of 12014888683 in words is "twelve billion, fourteen million, eight hundred eighty-eight thousand, six hundred eighty-three".
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