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1201505104021 is a prime number
BaseRepresentation
bin10001011110111111010…
…010001111000010010101
311020212021221211022112211
4101132333102033002111
5124141140301312041
62315544104113421
7152543262606265
oct21367722170225
94225257738484
101201505104021
11423612343012
12174a39765871
13893bc3761c1
14422203997a5
15213c1de2481
hex117bf48f095

1201505104021 has 2 divisors, whose sum is σ = 1201505104022. Its totient is φ = 1201505104020.

The previous prime is 1201505103979. The next prime is 1201505104057. The reversal of 1201505104021 is 1204015051021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1170537903396 + 30967200625 = 1081914^2 + 175975^2 .

It is an emirp because it is prime and its reverse (1204015051021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1201505104021 - 225 = 1201471549589 is a prime.

It is a super-2 number, since 2×12015051040212 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1201505103983 and 1201505104001.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201505104081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600752552010 + 600752552011.

It is an arithmetic number, because the mean of its divisors is an integer number (600752552011).

Almost surely, 21201505104021 is an apocalyptic number.

It is an amenable number.

1201505104021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201505104021 is an equidigital number, since it uses as much as digits as its factorization.

1201505104021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 400, while the sum is 22.

The spelling of 1201505104021 in words is "one trillion, two hundred one billion, five hundred five million, one hundred four thousand, twenty-one".