1201513440611 has 4 divisors (see below), whose sum is σ = 1310741935224. Its totient is φ = 1092284946000.

The previous prime is 1201513440581. The next prime is 1201513440623. The reversal of 1201513440611 is 1160443151021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201513440611 - 2¹⁰ = 1201513439587 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1201513442611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54614247290 + ... + 54614247311.

It is an arithmetic number, because the mean of its divisors is an integer number (327685483806).

Almost surely, 2^{1201513440611} is an apocalyptic number.

1201513440611 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1201513440611 is a deficient number, since it is larger than the sum of its proper divisors (109228494613).

1201513440611 is a wasteful number, since it uses less digits than its factorization.

1201513440611 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109228494612.

The product of its (nonzero) digits is 2880, while the sum is 29.

Adding to 1201513440611 its reverse (1160443151021), we get a palindrome (2361956591632).

The spelling of 1201513440611 in words is "one trillion, two hundred one billion, five hundred thirteen million, four hundred forty thousand, six hundred eleven".