Base | Representation |
---|---|
bin | 10110011000010100… |
… | …11000111010010011 |
3 | 1011000100201220201122 |
4 | 23030022120322103 |
5 | 144101343211011 |
6 | 5304131352455 |
7 | 603514413101 |
oct | 131412307223 |
9 | 34010656648 |
10 | 12015210131 |
11 | 5106300231 |
12 | 23b3a5272b |
13 | 119635b9c2 |
14 | 81da5ac71 |
15 | 4a4c773db |
hex | 2cc298e93 |
12015210131 has 2 divisors, whose sum is σ = 12015210132. Its totient is φ = 12015210130.
The previous prime is 12015210121. The next prime is 12015210167. The reversal of 12015210131 is 13101251021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12015210131 is a prime.
It is a super-2 number, since 2×120152101312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12015210121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007605065 + 6007605066.
It is an arithmetic number, because the mean of its divisors is an integer number (6007605066).
Almost surely, 212015210131 is an apocalyptic number.
12015210131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12015210131 is an equidigital number, since it uses as much as digits as its factorization.
12015210131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 12015210131 its reverse (13101251021), we get a palindrome (25116461152).
The spelling of 12015210131 in words is "twelve billion, fifteen million, two hundred ten thousand, one hundred thirty-one".
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