Base | Representation |
---|---|
bin | 11011010100011101010100… |
… | …010101011001011101011110 |
3 | 120202102112012212111001100210 |
4 | 123110131110111121131132 |
5 | 111222042100000013204 |
6 | 1103313330021033250 |
7 | 34210530306211515 |
oct | 3324352425313536 |
9 | 522375185431323 |
10 | 120153125001054 |
11 | 3531472174a962 |
12 | 11586592555826 |
13 | 5207511248982 |
14 | 219562988567c |
15 | dd56d276b389 |
hex | 6d475455975e |
120153125001054 has 16 divisors (see below), whose sum is σ = 252953947370880. Its totient is φ = 37943092105560.
The previous prime is 120153125000969. The next prime is 120153125001121. The reversal of 120153125001054 is 450100521351021.
It is a super-3 number, since 3×1201531250010543 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 526987390242 + ... + 526987390469.
It is an arithmetic number, because the mean of its divisors is an integer number (15809621710680).
Almost surely, 2120153125001054 is an apocalyptic number.
120153125001054 is an abundant number, since it is smaller than the sum of its proper divisors (132800822369826).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120153125001054 is a wasteful number, since it uses less digits than its factorization.
120153125001054 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1053974780735.
The product of its (nonzero) digits is 6000, while the sum is 30.
Adding to 120153125001054 its reverse (450100521351021), we get a palindrome (570253646352075).
The spelling of 120153125001054 in words is "one hundred twenty trillion, one hundred fifty-three billion, one hundred twenty-five million, one thousand, fifty-four".
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