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12015334121 = 71716476303
BaseRepresentation
bin10110011000010101…
…10111001011101001
31011000100222012210212
423030022313023221
5144101411142441
65304134150505
7603515440430
oct131412671351
934010865725
1012015334121
1151063853aa
1223b3ab2435
1311963a327b
1481da90117
154a4c9deeb
hex2cc2b72e9

12015334121 has 4 divisors (see below), whose sum is σ = 13731810432. Its totient is φ = 10298857812.

The previous prime is 12015334091. The next prime is 12015334141. The reversal of 12015334121 is 12143351021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12015334121 - 222 = 12011139817 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12015334141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 858238145 + ... + 858238158.

It is an arithmetic number, because the mean of its divisors is an integer number (3432952608).

Almost surely, 212015334121 is an apocalyptic number.

It is an amenable number.

12015334121 is a deficient number, since it is larger than the sum of its proper divisors (1716476311).

12015334121 is an equidigital number, since it uses as much as digits as its factorization.

12015334121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1716476310.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 12015334121 its reverse (12143351021), we get a palindrome (24158685142).

The spelling of 12015334121 in words is "twelve billion, fifteen million, three hundred thirty-four thousand, one hundred twenty-one".

Divisors: 1 7 1716476303 12015334121