12015543550117 has 4 divisors (see below), whose sum is σ = 12015987102496. Its totient is φ = 12015099997740.

The previous prime is 12015543550097. The next prime is 12015543550141. The reversal of 12015543550117 is 71105534551021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12015543550117 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12015543550117.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12015543550187) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221735553 + ... + 221789734.

It is an arithmetic number, because the mean of its divisors is an integer number (3003996775624).

Almost surely, 2^{12015543550117} is an apocalyptic number.

It is an amenable number.

12015543550117 is a deficient number, since it is larger than the sum of its proper divisors (443552379).

12015543550117 is an equidigital number, since it uses as much as digits as its factorization.

12015543550117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 443552378.

The product of its (nonzero) digits is 105000, while the sum is 40.

The spelling of 12015543550117 in words is "twelve trillion, fifteen billion, five hundred forty-three million, five hundred fifty thousand, one hundred seventeen".