Base | Representation |
---|---|
bin | 1010111011011011100010… |
… | …1111101101100101000101 |
3 | 1120112201201021102111122111 |
4 | 2232312320233231211011 |
5 | 3033333004444321432 |
6 | 41320044122501021 |
7 | 2350064505424135 |
oct | 256667057554505 |
9 | 46481637374574 |
10 | 12016123042117 |
11 | 3913011219aa7 |
12 | 142097b364771 |
13 | 692166ac65ac |
14 | 2d782501cac5 |
15 | 15c87861d347 |
hex | aedb8bed945 |
12016123042117 has 2 divisors, whose sum is σ = 12016123042118. Its totient is φ = 12016123042116.
The previous prime is 12016123042019. The next prime is 12016123042153. The reversal of 12016123042117 is 71124032161021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7008906784356 + 5007216257761 = 2647434^2 + 2237681^2 .
It is a cyclic number.
It is not a de Polignac number, because 12016123042117 - 215 = 12016123009349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12016123048117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6008061521058 + 6008061521059.
It is an arithmetic number, because the mean of its divisors is an integer number (6008061521059).
Almost surely, 212016123042117 is an apocalyptic number.
It is an amenable number.
12016123042117 is a deficient number, since it is larger than the sum of its proper divisors (1).
12016123042117 is an equidigital number, since it uses as much as digits as its factorization.
12016123042117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 31.
The spelling of 12016123042117 in words is "twelve trillion, sixteen billion, one hundred twenty-three million, forty-two thousand, one hundred seventeen".
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