Base | Representation |
---|---|
bin | 1010111011011011111010… |
… | …0010000110111101100100 |
3 | 1120112201222001010120000211 |
4 | 2232312332202012331210 |
5 | 3033333204323424424 |
6 | 41320101511545204 |
7 | 2350100064636400 |
oct | 256667642067544 |
9 | 46481861116024 |
10 | 12016220139364 |
11 | 3913061008661 |
12 | 14209a798b204 |
13 | 692180c61a9c |
14 | 2d7833c96100 |
15 | 15c881decb94 |
hex | aedbe886f64 |
12016220139364 has 27 divisors (see below), whose sum is σ = 24461689791987. Its totient is φ = 5149787832504.
The previous prime is 12016220139361. The next prime is 12016220139389. The reversal of 12016220139364 is 46393102261021.
The square root of 12016220139364 is 3466442.
It is a perfect power (a square), and thus also a powerful number.
It is not an unprimeable number, because it can be changed into a prime (12016220139361) by changing a digit.
It is a polite number, since it can be written in 8 ways as a sum of consecutive naturals, for example, 48406387 + ... + 48653989.
Almost surely, 212016220139364 is an apocalyptic number.
12016220139364 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
12016220139364 is the 3466442-nd square number.
It is an amenable number.
12016220139364 is an abundant number, since it is smaller than the sum of its proper divisors (12445469652623).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12016220139364 is an frugal number, since it uses more digits than its factorization.
12016220139364 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 495224 (or 247612 counting only the distinct ones).
The product of its (nonzero) digits is 93312, while the sum is 40.
The spelling of 12016220139364 in words is "twelve trillion, sixteen billion, two hundred twenty million, one hundred thirty-nine thousand, three hundred sixty-four".
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