120170000011 has 2 divisors, whose sum is σ = 120170000012. Its totient is φ = 120170000010.

The previous prime is 120169999967. The next prime is 120170000033. The reversal of 120170000011 is 110000071021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120170000011 - 2¹⁷ = 120169868939 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120169999946 and 120170000000.

It is not a weakly prime, because it can be changed into another prime (120170000311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60085000005 + 60085000006.

It is an arithmetic number, because the mean of its divisors is an integer number (60085000006).

Almost surely, 2^120170000011 is an apocalyptic number.

120170000011 is a deficient number, since it is larger than the sum of its proper divisors (1).

120170000011 is an equidigital number, since it uses as much as digits as its factorization.

120170000011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14, while the sum is 13.

Adding to 120170000011 its reverse (110000071021), we get a palindrome (230170071032).

The spelling of 120170000011 in words is "one hundred twenty billion, one hundred seventy million, eleven", and thus it is an aban number.