1201703 has 2 divisors, whose sum is σ = 1201704. Its totient is φ = 1201702.

The previous prime is 1201699. The next prime is 1201709. The reversal of 1201703 is 3071021.

It is a weak prime.

It is an emirp because it is prime and its reverse (3071021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1201703 - 2² = 1201699 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201709) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600851 + 600852.

It is an arithmetic number, because the mean of its divisors is an integer number (600852).

2^1201703 is an apocalyptic number.

1201703 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201703 is an equidigital number, since it uses as much as digits as its factorization.

1201703 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42, while the sum is 14.

The square root of 1201703 is about 1096.2221490191. Note that the first 3 decimals coincide. The cubic root of 1201703 is about 106.3161028106.

Adding to 1201703 its reverse (3071021), we get a palindrome (4272724).

The spelling of 1201703 in words is "one million, two hundred one thousand, seven hundred three".