1201749812477 has 4 divisors (see below), whose sum is σ = 1205613960096. Its totient is φ = 1197885664860.

The previous prime is 1201749812453. The next prime is 1201749812519. The reversal of 1201749812477 is 7742189471021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1201749812477 - 2³⁶ = 1133030335741 is a prime.

It is a super-2 number, since 2×1201749812477² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201749812447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1932073343 + ... + 1932073964.

It is an arithmetic number, because the mean of its divisors is an integer number (301403490024).

Almost surely, 2^{1201749812477} is an apocalyptic number.

It is an amenable number.

1201749812477 is a deficient number, since it is larger than the sum of its proper divisors (3864147619).

1201749812477 is an equidigital number, since it uses as much as digits as its factorization.

1201749812477 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3864147618.

The product of its (nonzero) digits is 1580544, while the sum is 53.

The spelling of 1201749812477 in words is "one trillion, two hundred one billion, seven hundred forty-nine million, eight hundred twelve thousand, four hundred seventy-seven".