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12018113 = 432691039
BaseRepresentation
bin101101110110…
…000111000001
3211121120202022
4231312013001
511034034423
61105331225
7204103142
oct55660701
924546668
1012018113
116869428
124036b15
13264a313
14184bac9
1510c5dc8
hexb761c1

12018113 has 8 divisors (see below), whose sum is σ = 12355200. Its totient is φ = 11683728.

The previous prime is 12018107. The next prime is 12018163. The reversal of 12018113 is 31181021.

12018113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12018113 - 212 = 12014017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12018091 and 12018100.

It is not an unprimeable number, because it can be changed into a prime (12018103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11048 + ... + 12086.

It is an arithmetic number, because the mean of its divisors is an integer number (1544400).

Almost surely, 212018113 is an apocalyptic number.

It is an amenable number.

12018113 is a deficient number, since it is larger than the sum of its proper divisors (337087).

12018113 is a wasteful number, since it uses less digits than its factorization.

12018113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1351.

The product of its (nonzero) digits is 48, while the sum is 17.

The square root of 12018113 is about 3466.7150156885. The cubic root of 12018113 is about 229.0579806530.

Adding to 12018113 its reverse (31181021), we get a palindrome (43199134).

The spelling of 12018113 in words is "twelve million, eighteen thousand, one hundred thirteen".

Divisors: 1 43 269 1039 11567 44677 279491 12018113