Base | Representation |
---|---|
bin | 10110011000101011… |
… | …01101011001010001 |
3 | 1011000120022200100112 |
4 | 23030111231121101 |
5 | 144103123140432 |
6 | 5304315131105 |
7 | 603551552465 |
oct | 131425553121 |
9 | 34016280315 |
10 | 12018177617 |
11 | 5107a477a6 |
12 | 23b4a43a95 |
13 | 1196b5a604 |
14 | 8201d04a5 |
15 | 4a51617b2 |
hex | 2cc56d651 |
12018177617 has 2 divisors, whose sum is σ = 12018177618. Its totient is φ = 12018177616.
The previous prime is 12018177601. The next prime is 12018177653. The reversal of 12018177617 is 71677181021.
12018177617 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11389371841 + 628805776 = 106721^2 + 25076^2 .
It is a cyclic number.
It is not a de Polignac number, because 12018177617 - 24 = 12018177601 is a prime.
It is not a weakly prime, because it can be changed into another prime (12018177517) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6009088808 + 6009088809.
It is an arithmetic number, because the mean of its divisors is an integer number (6009088809).
Almost surely, 212018177617 is an apocalyptic number.
It is an amenable number.
12018177617 is a deficient number, since it is larger than the sum of its proper divisors (1).
12018177617 is an equidigital number, since it uses as much as digits as its factorization.
12018177617 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32928, while the sum is 41.
The spelling of 12018177617 in words is "twelve billion, eighteen million, one hundred seventy-seven thousand, six hundred seventeen".
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