Search a number
-
+
12018313 = 64318691
BaseRepresentation
bin101101110110…
…001010001001
3211121121000201
4231312022021
511034041223
61105332201
7204103546
oct55661211
924547021
1012018313
11686959a
124037061
13264a438
14184bbcd
1510c5ead
hexb76289

12018313 has 4 divisors (see below), whose sum is σ = 12037648. Its totient is φ = 11998980.

The previous prime is 12018301. The next prime is 12018319. The reversal of 12018313 is 31381021.

12018313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12018313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12018319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8703 + ... + 9988.

It is an arithmetic number, because the mean of its divisors is an integer number (3009412).

Almost surely, 212018313 is an apocalyptic number.

It is an amenable number.

12018313 is a deficient number, since it is larger than the sum of its proper divisors (19335).

12018313 is an equidigital number, since it uses as much as digits as its factorization.

12018313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19334.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 12018313 is about 3466.7438613200. The cubic root of 12018313 is about 229.0592512724.

Adding to 12018313 its reverse (31381021), we get a palindrome (43399334).

The spelling of 12018313 in words is "twelve million, eighteen thousand, three hundred thirteen".

Divisors: 1 643 18691 12018313