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12018315 = 355411481
BaseRepresentation
bin101101110110…
…001010001011
3211121121000210
4231312022023
511034041230
61105332203
7204103551
oct55661213
924547023
1012018315
1168695a1
124037063
13264a43a
14184bbd1
1510c5eb0
hexb7628b

12018315 has 16 divisors (see below), whose sum is σ = 19277856. Its totient is φ = 6393600.

The previous prime is 12018301. The next prime is 12018319. The reversal of 12018315 is 51381021.

It is not a de Polignac number, because 12018315 - 24 = 12018299 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12018291 and 12018300.

It is not an unprimeable number, because it can be changed into a prime (12018319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7375 + ... + 8855.

It is an arithmetic number, because the mean of its divisors is an integer number (1204866).

Almost surely, 212018315 is an apocalyptic number.

12018315 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12018315 is a deficient number, since it is larger than the sum of its proper divisors (7259541).

12018315 is a wasteful number, since it uses less digits than its factorization.

12018315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2030.

The product of its (nonzero) digits is 240, while the sum is 21.

The square root of 12018315 is about 3466.7441497751. The cubic root of 12018315 is about 229.0592639785.

Adding to 12018315 its reverse (51381021), we get a palindrome (63399336).

The spelling of 12018315 in words is "twelve million, eighteen thousand, three hundred fifteen".

Divisors: 1 3 5 15 541 1481 1623 2705 4443 7405 8115 22215 801221 2403663 4006105 12018315