Base | Representation |
---|---|
bin | 1010111011100011101110… |
… | …1011101010110101011111 |
3 | 1120112221101101000020122122 |
4 | 2232320323223222311133 |
5 | 3033402004332010344 |
6 | 41321050114533155 |
7 | 2350203111511103 |
oct | 256707353526537 |
9 | 46487341006578 |
10 | 12018319797599 |
11 | 3913a392329a5 |
12 | 1421292b971bb |
13 | 692426c601cb |
14 | 2d7992a93903 |
15 | 15c9563e8aee |
hex | aee3baead5f |
12018319797599 has 4 divisors (see below), whose sum is σ = 12018479608080. Its totient is φ = 12018159987120.
The previous prime is 12018319797587. The next prime is 12018319797607. The reversal of 12018319797599 is 99579791381021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12018319797599 - 228 = 12018051362143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12018319797499) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79792382 + ... + 79942859.
It is an arithmetic number, because the mean of its divisors is an integer number (3004619902020).
Almost surely, 212018319797599 is an apocalyptic number.
12018319797599 is a deficient number, since it is larger than the sum of its proper divisors (159810481).
12018319797599 is an equidigital number, since it uses as much as digits as its factorization.
12018319797599 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 159810480.
The product of its (nonzero) digits is 77157360, while the sum is 71.
The spelling of 12018319797599 in words is "twelve trillion, eighteen billion, three hundred nineteen million, seven hundred ninety-seven thousand, five hundred ninety-nine".
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