Base | Representation |
---|---|
bin | 100011110100011… |
… | …1101110010110111 |
3 | 10002202121220221021 |
4 | 1013220331302313 |
5 | 4430142434312 |
6 | 315133202011 |
7 | 41533106314 |
oct | 10750756267 |
9 | 3082556837 |
10 | 1201921207 |
11 | 5674a9213 |
12 | 296630307 |
13 | 162017aa6 |
14 | b58add0b |
15 | 707b9c07 |
hex | 47a3dcb7 |
1201921207 has 2 divisors, whose sum is σ = 1201921208. Its totient is φ = 1201921206.
The previous prime is 1201921103. The next prime is 1201921213. The reversal of 1201921207 is 7021291021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201921207 is a prime.
It is a super-2 number, since 2×12019212072 = 2889229175672673698, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201921807) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600960603 + 600960604.
It is an arithmetic number, because the mean of its divisors is an integer number (600960604).
Almost surely, 21201921207 is an apocalyptic number.
1201921207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201921207 is an equidigital number, since it uses as much as digits as its factorization.
1201921207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 25.
The square root of 1201921207 is about 34668.7352956522. The cubic root of 1201921207 is about 1063.2253743267.
The spelling of 1201921207 in words is "one billion, two hundred one million, nine hundred twenty-one thousand, two hundred seven".
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