Base | Representation |
---|---|
bin | 110111111110000010… |
… | …0110000110001111011 |
3 | 102111020110202101201121 |
4 | 1233330010300301323 |
5 | 3432123431130203 |
6 | 131114353530111 |
7 | 11453333355052 |
oct | 1577404606173 |
9 | 374213671647 |
10 | 120193223803 |
11 | 46a78a3a014 |
12 | 1b364573937 |
13 | b44623b293 |
14 | 5b62c83399 |
15 | 31d6e220bd |
hex | 1bfc130c7b |
120193223803 has 2 divisors, whose sum is σ = 120193223804. Its totient is φ = 120193223802.
The previous prime is 120193223791. The next prime is 120193223837. The reversal of 120193223803 is 308322391021.
It is an a-pointer prime, because the next prime (120193223837) can be obtained adding 120193223803 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120193223803 - 221 = 120191126651 is a prime.
It is a super-2 number, since 2×1201932238032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120193223203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60096611901 + 60096611902.
It is an arithmetic number, because the mean of its divisors is an integer number (60096611902).
Almost surely, 2120193223803 is an apocalyptic number.
120193223803 is a deficient number, since it is larger than the sum of its proper divisors (1).
120193223803 is an equidigital number, since it uses as much as digits as its factorization.
120193223803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 120193223803 in words is "one hundred twenty billion, one hundred ninety-three million, two hundred twenty-three thousand, eight hundred three".
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