Base | Representation |
---|---|
bin | 10001011111011101011… |
… | …111111101110100100011 |
3 | 11020220121021200022112211 |
4 | 101133131133331310203 |
5 | 124143210034120003 |
6 | 2320110253102551 |
7 | 152561656406404 |
oct | 21373537756443 |
9 | 4226537608484 |
10 | 1202012020003 |
11 | 4238524a3543 |
12 | 174b5b487a57 |
13 | 894703b01a2 |
14 | 4226b8319ab |
15 | 2140167496d |
hex | 117dd7fdd23 |
1202012020003 has 2 divisors, whose sum is σ = 1202012020004. Its totient is φ = 1202012020002.
The previous prime is 1202012019991. The next prime is 1202012020019. The reversal of 1202012020003 is 3000202102021.
It is a weak prime.
It is an emirp because it is prime and its reverse (3000202102021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1202012020003 - 29 = 1202012019491 is a prime.
It is a super-3 number, since 3×12020120200033 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1202012020093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601006010001 + 601006010002.
It is an arithmetic number, because the mean of its divisors is an integer number (601006010002).
Almost surely, 21202012020003 is an apocalyptic number.
1202012020003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202012020003 is an equidigital number, since it uses as much as digits as its factorization.
1202012020003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 1202012020003 its reverse (3000202102021), we get a palindrome (4202214122024).
The spelling of 1202012020003 in words is "one trillion, two hundred two billion, twelve million, twenty thousand, three".
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