Base | Representation |
---|---|
bin | 11011010101001011000010… |
… | …001001111001011000111111 |
3 | 120202121012220211120001202221 |
4 | 123111023002021321120333 |
5 | 111223343112300321002 |
6 | 1103352044532230211 |
7 | 34214215604640034 |
oct | 3325130211713077 |
9 | 522535824501687 |
10 | 120202212120127 |
11 | 35333521092a65 |
12 | 11593bb176b367 |
13 | 520c034b32067 |
14 | 2197b64c6538b |
15 | dd6b06ddcc37 |
hex | 6d52c227963f |
120202212120127 has 2 divisors, whose sum is σ = 120202212120128. Its totient is φ = 120202212120126.
The previous prime is 120202212120083. The next prime is 120202212120167. The reversal of 120202212120127 is 721021212202021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120202212120127 is a prime.
It is a super-2 number, since 2×1202022121201272 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120202212120167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60101106060063 + 60101106060064.
It is an arithmetic number, because the mean of its divisors is an integer number (60101106060064).
Almost surely, 2120202212120127 is an apocalyptic number.
120202212120127 is a deficient number, since it is larger than the sum of its proper divisors (1).
120202212120127 is an equidigital number, since it uses as much as digits as its factorization.
120202212120127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 120202212120127 its reverse (721021212202021), we get a palindrome (841223424322148).
The spelling of 120202212120127 in words is "one hundred twenty trillion, two hundred two billion, two hundred twelve million, one hundred twenty thousand, one hundred twenty-seven".
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