12020333131330 has 32 divisors (see below), whose sum is σ = 22909779834480. Its totient is φ = 4525215160320.

The previous prime is 12020333131321. The next prime is 12020333131351. The reversal of 12020333131330 is 3313133302021.

It can be written as a sum of positive squares in 8 ways, for example, as 8942438332881 + 3077894798449 = 2990391^2 + 1754393^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12020333131295 and 12020333131304.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8591016 + ... + 9891724.

Almost surely, 2^{12020333131330} is an apocalyptic number.

12020333131330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12020333131330 is a deficient number, since it is larger than the sum of its proper divisors (10889446703150).

12020333131330 is a wasteful number, since it uses less digits than its factorization.

12020333131330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1355094.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 12020333131330 its reverse (3313133302021), we get a palindrome (15333466433351).

The spelling of 12020333131330 in words is "twelve trillion, twenty billion, three hundred thirty-three million, one hundred thirty-one thousand, three hundred thirty".