1202043301159 has 2 divisors, whose sum is σ = 1202043301160. Its totient is φ = 1202043301158.

The previous prime is 1202043301097. The next prime is 1202043301171. The reversal of 1202043301159 is 9511033402021.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1202043301159 is a prime.

It is a super-2 number, since 2×1202043301159² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1202043301159.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1202041301159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601021650579 + 601021650580.

It is an arithmetic number, because the mean of its divisors is an integer number (601021650580).

Almost surely, 2^{1202043301159} is an apocalyptic number.

1202043301159 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202043301159 is an equidigital number, since it uses as much as digits as its factorization.

1202043301159 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 31.

The spelling of 1202043301159 in words is "one trillion, two hundred two billion, forty-three million, three hundred one thousand, one hundred fifty-nine".