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120204421313 = 472557540879
BaseRepresentation
bin110111111110010111…
…1011110100011000001
3102111021020211021211012
41233330233132203001
53432134312440223
6131115433530305
711453530502624
oct1577457364301
9374236737735
10120204421313
1146a84297959
121b368273995
13b44865bc22
145b64559dbb
1531d7dd4c78
hex1bfcbde8c1

120204421313 has 4 divisors (see below), whose sum is σ = 122761962240. Its totient is φ = 117646880388.

The previous prime is 120204421303. The next prime is 120204421319. The reversal of 120204421313 is 313124402021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120204421313 - 218 = 120204159169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120204421319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1278770393 + ... + 1278770486.

It is an arithmetic number, because the mean of its divisors is an integer number (30690490560).

Almost surely, 2120204421313 is an apocalyptic number.

It is an amenable number.

120204421313 is a deficient number, since it is larger than the sum of its proper divisors (2557540927).

120204421313 is an equidigital number, since it uses as much as digits as its factorization.

120204421313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2557540926.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 120204421313 its reverse (313124402021), we get a palindrome (433328823334).

The spelling of 120204421313 in words is "one hundred twenty billion, two hundred four million, four hundred twenty-one thousand, three hundred thirteen".

Divisors: 1 47 2557540879 120204421313