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1202100122143 is a prime number
BaseRepresentation
bin10001011111100010110…
…000000011001000011111
311020220211102110100222001
4101133202300003020133
5124143400112402033
62320123121303131
7152564106306064
oct21374260031037
94226742410861
101202100122143
114238981a8a28
12174b84a94aa7
138948571932b
1442279406c6b
1521409278e7d
hex117e2c0321f

1202100122143 has 2 divisors, whose sum is σ = 1202100122144. Its totient is φ = 1202100122142.

The previous prime is 1202100122137. The next prime is 1202100122173. The reversal of 1202100122143 is 3412210012021.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1202100122143 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1202100122143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1202100122173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601050061071 + 601050061072.

It is an arithmetic number, because the mean of its divisors is an integer number (601050061072).

Almost surely, 21202100122143 is an apocalyptic number.

1202100122143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202100122143 is an equidigital number, since it uses as much as digits as its factorization.

1202100122143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1202100122143 its reverse (3412210012021), we get a palindrome (4614310134164).

The spelling of 1202100122143 in words is "one trillion, two hundred two billion, one hundred million, one hundred twenty-two thousand, one hundred forty-three".