Base | Representation |
---|---|
bin | 10001011111100010110… |
… | …000000011001000011111 |
3 | 11020220211102110100222001 |
4 | 101133202300003020133 |
5 | 124143400112402033 |
6 | 2320123121303131 |
7 | 152564106306064 |
oct | 21374260031037 |
9 | 4226742410861 |
10 | 1202100122143 |
11 | 4238981a8a28 |
12 | 174b84a94aa7 |
13 | 8948571932b |
14 | 42279406c6b |
15 | 21409278e7d |
hex | 117e2c0321f |
1202100122143 has 2 divisors, whose sum is σ = 1202100122144. Its totient is φ = 1202100122142.
The previous prime is 1202100122137. The next prime is 1202100122173. The reversal of 1202100122143 is 3412210012021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1202100122143 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1202100122143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1202100122173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601050061071 + 601050061072.
It is an arithmetic number, because the mean of its divisors is an integer number (601050061072).
Almost surely, 21202100122143 is an apocalyptic number.
1202100122143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202100122143 is an equidigital number, since it uses as much as digits as its factorization.
1202100122143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 1202100122143 its reverse (3412210012021), we get a palindrome (4614310134164).
The spelling of 1202100122143 in words is "one trillion, two hundred two billion, one hundred million, one hundred twenty-two thousand, one hundred forty-three".
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