Base | Representation |
---|---|
bin | 10001011111100011011… |
… | …001111110001101110101 |
3 | 11020220212012010201021202 |
4 | 101133203121332031311 |
5 | 124143410421041203 |
6 | 2320124153022245 |
7 | 152564301600455 |
oct | 21374331761565 |
9 | 4226765121252 |
10 | 1202111112053 |
11 | 4238a34248a5 |
12 | 174b886b4985 |
13 | 89487a96637 |
14 | 4227aa67d65 |
15 | 2140a1ea388 |
hex | 117e367e375 |
1202111112053 has 2 divisors, whose sum is σ = 1202111112054. Its totient is φ = 1202111112052.
The previous prime is 1202111111941. The next prime is 1202111112089. The reversal of 1202111112053 is 3502111112021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1146908199844 + 55202912209 = 1070938^2 + 234953^2 .
It is a cyclic number.
It is not a de Polignac number, because 1202111112053 - 210 = 1202111111029 is a prime.
It is a super-2 number, since 2×12021111120532 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1202111112253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601055556026 + 601055556027.
It is an arithmetic number, because the mean of its divisors is an integer number (601055556027).
Almost surely, 21202111112053 is an apocalyptic number.
It is an amenable number.
1202111112053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202111112053 is an equidigital number, since it uses as much as digits as its factorization.
1202111112053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 20.
Adding to 1202111112053 its reverse (3502111112021), we get a palindrome (4704222224074).
The spelling of 1202111112053 in words is "one trillion, two hundred two billion, one hundred eleven million, one hundred twelve thousand, fifty-three".
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