Base | Representation |
---|---|
bin | 1010111011101110001000… |
… | …0111011111110010101011 |
3 | 1120120012120222020102111202 |
4 | 2232323202013133302223 |
5 | 3033423214200012001 |
6 | 41322231143514415 |
7 | 2350332236001236 |
oct | 256734207376253 |
9 | 46505528212452 |
10 | 12021112110251 |
11 | 391514143a802 |
12 | 1421932158a0b |
13 | 6927805c840a |
14 | 2d7b7987641d |
15 | 15ca6b61596b |
hex | aeee21dfcab |
12021112110251 has 2 divisors, whose sum is σ = 12021112110252. Its totient is φ = 12021112110250.
The previous prime is 12021112110211. The next prime is 12021112110253. The reversal of 12021112110251 is 15201121112021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12021112110251 - 218 = 12021111848107 is a prime.
Together with 12021112110253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12021112110253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010556055125 + 6010556055126.
It is an arithmetic number, because the mean of its divisors is an integer number (6010556055126).
Almost surely, 212021112110251 is an apocalyptic number.
12021112110251 is a deficient number, since it is larger than the sum of its proper divisors (1).
12021112110251 is an equidigital number, since it uses as much as digits as its factorization.
12021112110251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 20.
Adding to 12021112110251 its reverse (15201121112021), we get a palindrome (27222233222272).
The spelling of 12021112110251 in words is "twelve trillion, twenty-one billion, one hundred twelve million, one hundred ten thousand, two hundred fifty-one".
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