12021121219973 has 2 divisors, whose sum is σ = 12021121219974. Its totient is φ = 12021121219972.

The previous prime is 12021121219969. The next prime is 12021121220011. The reversal of 12021121219973 is 37991212112021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10750221235009 + 1270899984964 = 3278753^2 + 1127342^2 .

It is a cyclic number.

It is not a de Polignac number, because 12021121219973 - 2² = 12021121219969 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12021121219973.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12021121219673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010560609986 + 6010560609987.

It is an arithmetic number, because the mean of its divisors is an integer number (6010560609987).

Almost surely, 2^{12021121219973} is an apocalyptic number.

It is an amenable number.

12021121219973 is a deficient number, since it is larger than the sum of its proper divisors (1).

12021121219973 is an equidigital number, since it uses as much as digits as its factorization.

12021121219973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216, while the sum is 41.

The spelling of 12021121219973 in words is "twelve trillion, twenty-one billion, one hundred twenty-one million, two hundred nineteen thousand, nine hundred seventy-three".